[填空题]
The radius of a circle fsn5j-( rr5ozdnj5ya5v(5 l lof wire is measured to be 10.0 ± 0.5/2czphvkt8(f. ta. gb cm. What is the percentage error in the area of the loop? % What is the percentage error in the circumference of the loop? %
参考答案: 空格1: 10.0
空格2: 5.0
本题详细解析: First calculate the percentage error in the radius of the logi ss9sy(ir,, op: $$ \frac{\Delta \mathrm{r}}{\mathrm{r}}=\frac{0.5}{10}=5 \% $$ The area of a circle is $A=\pi r^2$ and so the percentage error on the area of the loop will be twice the percentage error of the radius, $\Delta A=10 \%$.
Post time 2024-8-21 21:38:19