[填空题]
A force of 10.0 ± 0.2 N is applied to a mass of 2.0 ± 0.01 kg, causing / ,vlk 0t6fijwit to ac bw3vl79y,bhyev /c y7celerate. What is the percentage uncertainty of its acceleybwhvy9y 7/vlc3e7b , ration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the.q;bt4- 4ggk*9l,ruzkhmua j formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.