[填空题]
A force of 10.0 ± 0.2 N is apv,r ls :,ih;rmi33rfdplied to a mass of 2.0 ± 0.01 kg *jif5cruth-k97, vy0 x* qfbq, causing it to accelerate. What rhf* yqtf0,j9vci q7 -5bukx* is the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using thi5cv0xd 3k py58;kmvcd,w ye;e formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.