[填空题]
A force of 10.0 ± 0.2 N is applied to a mass of 2.0 ±0j9rne9y)n f aegdajhcj(*cb775 9et 0.,57lfphs chk4mff(5m 01 kg, causing it to accelerate. What iscf45hsfp,h5 7f(ml k m the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated using the formula: rgme 0kahdo1k9v 7)/7qcepm 7$$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19