[填空题]
A force of 10.0 ± 0.2 N iszsc y2./huxtnm yivu1qz)pl x - (+98i applied to a mass of 2.0 ± 0.01 kg, c k.e qtlc.xl/tps2 a(iun78) 1piy z2fausing it to accelerate. What is the percentage uncertainx 2lk7.12.ppya/)tnsi( lz c 8qtieuf ty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated usi izyowf ..f;-mng the formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.