[填空题]
For an object of masok-z*a 34 1-vra fby0jgc(gc e+v uws4pr/4;fa 7tyu x x2t)sl x;kh(es $(2.0 \pm 0.1) \mathrm{kg}$, what percentage uncertainty in the velocity will give a $7.0 \%$ uncertainty in the kinetic energy ($KE = \frac{1}{2}mv^2$) ? % (do not include the percent sign in your final result)
参考答案: 1.0
本题详细解析: The percentage error in the kinetic energy ca /-dua.0a 3 rceq)u,c-gauvi8hu.mgzn be calculated as:
$$ \frac{\Delta E_K}{E_K}=\frac{\Delta m}{m}+2 \frac{\Delta v}{v} $$ Hence: $$ \begin{aligned} &0.07=\frac{0.1}{2.0}+2 \frac{\Delta v}{v} \\ &0.07=0.05+2 \frac{\Delta v}{v} \end{aligned} $$ and: $$ \frac{\Delta v}{v}=0.01 $$
So it is 1 percent.