[填空题]
The potential differenm p.d+ ihcj-l+,s ,cqlwxjz9 2ce ($V$) across a resistor is measured with a digital voltmeter to be $0.10 \; V$ . What is the percentage uncertainty in $V^2$ ? % (please only input numerical value without units and without the $\pm$ symbol.)
参考答案: 20.00
本题详细解析: The voltmeter is a digital device and so the uncertainty is the smallest ve/gunndh187r+wm: m1 c ;onapalue which it can rdn7cwm 1nh8ue m/ a :pgnor1;+ecord, $0.01 \mathrm{~V}$. This is a $10 \%$ uncertainty on the $0.10 \mathrm{~V}$ measurement. The uncertainty in $V^2$ will be twice this, giving $20 \%$.