[填空题]
A force of 10.0 ± 0.2 N is applied to a mass ,m;-gi v)i kkj2c jj b,hw+od4of 2.0 ± 0.e4)8n6aa bb byvlyqv4 ec c6t 5ezc ce.93,dl101 kg, causing it to accelerate. What is 9,ev1 aed4bc l lv.czne 68bty3 y4c5c)eaq6b the percentage uncertainty of its acceleration? % (do not include the percent sign in your result)
参考答案: 2.50
本题详细解析: The acceleration is calculated lmnq5v 2m s44uusing the formula: $$ a=\frac{F}{m} $$ so the percentage uncertainty on the acceleration is the sum of the percentage error on the force and on the mass. The percentage uncertainty on the force is: $$ \frac{0.2}{10.0} \times 100 \%=2 \% $$ The percentage uncertainty on the mass is:
$$ \frac{0.1}{2.0} \times 100 \%=5 \% . $$ Hence the percentage error on the acceleration will be $7 \%$.
Post time 2024-8-21 21:38:19